Easymathsteps

 Graphing Inequalities on a Number Line Visualizing inequalities on a number line helps us understand which values satisfy an inequality. This lesson shows you how to graph them step by step. --- 🔸 How to Graph an Inequality Steps to follow: 1. Draw a number line 2. Mark the value in the inequality 3. Use: Open circle (○) for or — value not included Closed circle (●) for or — value included 4. Shade the direction: Left for less than Right for greater than --- ✅ Example 1: Graph  Open circle at 4 Shade to the left <=========○---------  4 ✅ Final Answer: x < 4 --- ✅ Example 2: Graph  Closed circle at –2 Shade to the right --------●=========> -2 ✅ Final Answer: x ≥ –2 --- 🔸 Quick Summary: Symbols and Circles Symbol Type of Dot Includes the Number?  or Open circle (○) ❌ No  or Closed circle (●) ✅ Yes 📝 Practice Questions: Practice: Graph the following inequalities on a number line. 1. x > 2 2. x ≤ 0 3. x ≥ –5 4. x < –1 5. x ≥ 7 📘 Keep l...

 What are Inequalities? In algebra, not all expressions are equal — some are greater or less than others. Inequalities help us compare values that are not exactly equal. --- 🔸 What is an Inequality? An inequality is a mathematical sentence that shows the relationship between two expressions using comparison symbols. --- 🔸 Common Inequality Symbols Symbol Meaning Example > Greater than x > 4 < Less than x < 7 ≥ Greater than or equal to x ≥ 2 ≤ Less than or equal to x ≤ 5 --- 🔸 Difference Between Equations and Inequalities An equation gives one exact answer:   ✅ x = 3 An inequality gives many possible answers:   ✅ x > 3 (x could be 4, 5, 100…) --- 🔸 Solving Inequalities Solving inequalities is almost the same as solving equations: You can add, subtract, multiply, or divide both sides. BUT, if you multiply or divide by a negative number, flip the sign. --- ✅ Examples Example 1: Solve x + 4 < 9 Step: Subtract 4 from both sides Answer: x < 5 Example 2: Solve –2x...

Like and Unlike Terms In algebra, knowing which terms you can combine is important. That’s where the concept of like terms and unlike terms comes in. --- ✅ What Are Like Terms? Like terms are terms that: Have the same variable, and Have the same exponent (power) Only the coefficients (numbers in front) can be different. Examples of Like Terms: 2x and 5x 3a² and -7a² x and -x --- ❌ What Are Unlike Terms? Unlike terms have: Different variables, or The same variables but different powers Examples of Unlike Terms: 3x and 4y 2a and 2a² x and x² --- ✍️ Examples Example 1: Which of the following are like terms? 5y, -2y, 3x, 7y ✅ Like terms: 5y, -2y, 7y ❌ Unlike term: 3x Example 2: Group the like terms: 2m, 3n, -4m, 5n, 6 Like terms: 2m, -4m and 3n, 5n Constant: 6 (unlike any other) --- 📝 Practice Questions 1. Identify the like and unlike terms in this set: 6x, -3x, 4y, x² 2. Group the like terms in: 2a, 3b, 5a, -2b, 7 --- ✅ Keep learning! Stay tuned for the next topic! 📖 Visit our blog: eas...

An algebraic expression is a combination of numbers, letters (variables), and mathematical operations such as addition, subtraction, multiplication, or division. ✅ Key Parts of an Expression 1. Term A term is any part of the expression that is separated by a plus (+) or minus (−) sign. Example: In the expression 3x + 4, there are two terms: 3x and 4. 2. Coefficient A coefficient is the numerical part of a term with a variable. Example: In 3x, the coefficient is 3. 3. Variable A variable is a symbol (often a letter like x or y) that represents an unknown value. Example: In 3x + 4, the variable is x. 4. Constant A constant is a fixed value with no variable attached. Example: In 3x + 4, the constant is 4. --- ✍️ Examples Example 1: Expression: 7y − 2 Terms: 7y, −2 Coefficient: 7 Variable: y Constant: −2 Example 2: Expression: 5a + 3b − 7 Terms: 5a, 3b, −7 Coefficients: 5, 3 Variables: a, b Constant: −7 --- 📝 Practice Questions 1. Identify the terms, coefficients, and constants in the exp...

Welcome back to EasyMathsGuid! In this lesson, we’re solving real-life word problems using fractions. These help you apply math to everyday situations. --- 🔶 Word Problem 1 A school bought 7 1/2 kilograms of rice for a math club event. They used 2 2/3 kilograms for lunch and 1 3/4 kilograms for dinner. Question: How much rice is left? --- 🧮 Solution: Step 1: Convert mixed numbers: 7 1/2 = 15/2 2 2/3 = 8/3 1 3/4 = 7/4 Step 2: Add lunch and dinner used: 8/3 = 32/12 7/4 = 21/12 Total used = 32/12 + 21/12 = 53/12 Step 3: Total rice = 15/2 = 90/12 Step 4: Leftover = 90/12 - 53/12 = 37/12 = 3 1/12 ✅ Final Answer: 3 1/12 kg of rice is left --- 🔷 Word Problem 2 Mary read 3/4 of a book in the morning and 2/5 in the evening. How much of the book did she read in total? --- 🧮 Solution: LCM of 4 and 5 = 20 3/4 = 15/20 2/5 = 8/20 Total = 15/20 + 8/20 = 23/20 = 1 3/20 ✅ Answer: Mary read 1 3/20 of the book --- 🔷 Word Problem 3 A water tank contains 5 1/2 liters of water. If 3 3/4 liters are used...

This lesson shows how to solve real-world problems where fractions are involved in the equation. It builds directly from Lesson 12 on dividing fractions. --- 🔍 Steps to Solve: 1. Read the word problem carefully. 2. Let the unknown number be x. 3. Translate the words into a fraction-based equation. 4. Solve by multiplying by the reciprocal or using the LCM method. 5. State your final answer clearly. --- 📘 Example 1: Problem: One-third of a number is 9. What is the number? Solution: Let the number be x. (1/3) × x = 9 Multiply both sides by 3: x = 9 × 3 = 27 ✅ Final Answer: 27 --- 📘 Example 2: Problem: Half a number minus 2 equals 3. Find the number. Solution: (1/2) × x - 2 = 3 Add 2 to both sides: (1/2) × x = 5 Multiply both sides by 2: x = 10 ✅ Final Answer: 10 --- 📘 Example 3: Problem: Two-thirds of a number equals 16. What is the number? Solution: (2/3) × x = 16 Multiply both sides by 3/2: x = 16 × (3/2) = 48/2 = 24 ✅ Final Answer: 24 --- 📝 Practice Questions: 1. One-fourth of a ...

In this lesson, we’ll learn how to solve equations where a variable is divided by a fraction — a key part of mastering algebra. --- ✏️ Concept: When solving an equation like: x ÷ (a/b) = c, you multiply both sides by the reciprocal of the fraction. > ✨ Remember: Dividing by a fraction is the same as multiplying by its reciprocal. --- 📘 Example 1: Solve: x ÷ (2/3) = 6 👉 Multiply both sides by 3/2 (the reciprocal of 2/3): x = 6 × (3/2) = 18/2 = 9 ✅ Final Answer: x = 9 --- 📘 Example 2: Solve: x ÷ (5/4) = 8 Multiply both sides by 4/5: x = 8 × (4/5) = 32/5 = 6.4 or 6⅖ ✅ Final Answer: x = 6.4 --- 📝 Practice Questions: 1. x ÷ (3/4) = 12 2. x ÷ (1/2) = 10 3. x ÷ (5/6) = 18 4. x ÷ (2/5) = 7 5. x ÷ (4/7) = 14 --- ✅ Answers: 1. x = 12 × (4/3) = 16 2. x = 10 × (2/1) = 20 3. x = 18 × (6/5) = 21.6 4. x = 7 × (5/2) = 17.5 5. x = 14 × (7/4) = 24.5 --- 📚 Continue learning at: 🔗 Blog: https://easymathsteps.blogspot.com 🌐 Website: https://www.easymathsguid.com.ng

Now that we've solved equations with fractions, let’s learn how to solve equations where you need to multiply fractions to get the variable. --- ✏️ Concept: To solve equations like: (fraction) × x = value You need to multiply both sides of the equation by the reciprocal of the fraction to isolate x. > ✨ The reciprocal of a fraction is when you flip the numerator and denominator. --- 📘 Example 1: Solve: (2/3) × x = 6 To eliminate the fraction, multiply both sides by the reciprocal of 2/3, which is 3/2: x = 6 × (3/2) x = 18/2 = 9 ✅ Final Answer: x = 9 --- 📘 Example 2: Solve: (5/8) × x = 10 Multiply both sides by 8/5: x = 10 × (8/5) x = 80/5 = 16 ✅ Final Answer: x = 16 --- 📝 Practice Questions: 1. (3/4) × x = 9 2. (7/2) × x = 14 3. (4/5) × x = 20 4. (2/3) × x = 10 5. (9/10) × x = 18 --- ✅ Answers: 1. x = 12 2. x = 4 3. x = 25 4. x = 15 5. x = 20 --- 📘 Want more lessons? Visit us: 🔗 Blog: https://easymathsteps.blogspot.com 🌐 Website:https://www.easymathsguid.com.ng 

🧮 Example: Solve: (2x/3) − (1/6) = (x/2) + (1/3) --- 🔍 Step 1: Identify the Denominators The denominators are: 3, 6, 2, and 3 To simplify, we eliminate the fractions by multiplying all terms by the Least Common Multiple (LCM) of these numbers. --- ✏️ Step 2: Find the LCM Let’s list a few multiples: Multiples of 2: 2, 4, 6, 8... Multiples of 3: 3, 6, 9... Multiples of 6: 6, 12, 18... ✅ The smallest common multiple is 6 So the LCM = 6 --- ✏️ Step 3: Multiply Every Term by 6 Now apply this to the equation: 6 × (2x/3) − 6 × (1/6) = 6 × (x/2) + 6 × (1/3) Now simplify: 6 × (2x/3) = 4x 6 × (1/6) = 1 6 × (x/2) = 3x 6 × (1/3) = 2 Now rewrite the new equation: 4x − 1 = 3x + 2 --- ✏️ Step 4: Solve the New Equation Now solve like a regular linear equation: 4x − 1 = 3x + 2 Subtract 3x from both sides: x − 1 = 2 Add 1 to both sides: x = 3 --- ✅ Final Answer: x = 3 --- 💡 Quick Tip: When dealing with equations that include fractions: Always begin by finding the LCM of all denominators. Multiply eve...

Solve: (1/2)x + (1/4) = 3/4 --- 🔍 Step 1: Understand the Problem This equation contains fractions, which makes it a bit harder to solve directly. To make it simpler, we will remove the fractions by using the LCM (Least Common Multiple) of the denominators. --- ✏️ Step 2: Find the LCM of the Denominators (2 and 4) Let’s list a few multiples: Multiples of 2: 2, 4, 6, 8, 10... Multiples of 4: 4, 8, 12... 👉 The LCM of 2 and 4 is 4 --- ✏️ Step 3: Multiply Every Term by the LCM Now multiply every term in the equation by 4 to remove the fractions: 4 × (1/2)x + 4 × (1/4) = 4 × (3/4) This simplifies to: 2x + 1 = 3 --- ✏️ Step 4: Solve the New Equation Now solve: 2x + 1 = 3 Subtract 1 from both sides: 2x = 2 Now divide both sides by 2: x = 1 ✅ Final Answer: x = 1 ---

🧮 Example: Solve: 2(x + 3) = 3(x - 1) --- ✏️ Step 1: Expand Both Sides Use the distributive property: Left side: 2(x + 3) = 2x + 6 Right side: 3(x - 1) = 3x - 3 Now your equation becomes: 2x + 6 = 3x - 3 --- ✏️ Step 2: Move Variables to One Side Subtract 2x from both sides: 2x - 2x + 6 = 3x - 2x - 3   6 = x - 3 --- ✏️ Step 3: Solve for x Add 3 to both sides: 6 + 3 = x - 3 + 3   9 = x --- ✅ Final Answer: x = 9 --- 💡 Quick Tip: 👉 Always expand brackets first 👉 Move all variable terms to one side 👉 Move numbers to the opposite side 👉 Solve carefully, step by step! --- 🔗 Follow for More Lessons: 🌐 Website: www.easymathsguid.com.ng 📘 Blog: easymathsteps.blogspot.com ---

🧮 Example: Solve: 2(x + 3) = 14 --- ✏️ Step 1: Expand the Bracket Use the distributive property: Multiply 2 by x and 3: 2 × x = 2x   2 × 3 = 6 So the equation becomes: 2x + 6 = 14 --- ✏️ Step 2: Solve the Equation Now subtract 6 from both sides: 2x = 14 - 6   2x = 8 Divide both sides by 2: x = 8 ÷ 2   x = 4 --- ✅ Final Answer: x = 4 --- 💡 Quick Tip: Always expand the brackets first before solving the equation. Then follow the steps you've already learned: move constants, isolate the variable, and solve. --- 🔗 Follow Easymathsguid for More Lessons: 🌐 Website: www.easymathsguid.com.ng 📘 Blog: easymathsteps.blogspot.com

🧮 Example: Solve: 3x + 4 = 2x + 9 --- ✏️ Step 1: Move variables to one side Subtract 2x from both sides: 3x - 2x + 4 = 2x - 2x + 9 x + 4 = 9 --- ✏️ Step 2: Move constants to the other side Subtract 4 from both sides: x + 4 - 4 = 9 - 4 x = 5 --- ✅ Final Answer: x = 5 --- 📝 Quick Tip: Always move all the x terms to one side and the numbers to the other before solving. Then simplify step-by-step. --- 🔗 Follow for more: 🌐 Website: www.easymath sguid.com.ng 📘 Blog: easymathsteps.blogspot.com

In earlier lessons, we solved equations like: x + 3 = 7   But now we’ll learn how to solve when x appears on both sides of the equation. 🔹 Example 1: Solve: x + 2 = x + 5 Step 1: Subtract x from both sides: x + 2 − x = x + 5 − x   2 = 5 This is false → ❌ No solution --- 🔹 Example 2: Solve: 2x + 3 = x + 7 Step 1: Subtract x from both sides: 2x + 3 − x = x + 7 − x   x + 3 = 7 Step 2: Subtract 3 from both sides: x = 4 ✅ Answer: x = 4 --- 🔹 Example 3: Solve: 3x − 2 = 2x + 5 Step 1: Subtract 2x from both sides: x − 2 = 5 Step 2: Add 2 to both sides: x = 7 ✅ Answer: x = 7 --- ✨ Tip: Always move all x terms to one side and numbers to the other. --- ✅ Practice Questions: 1. 2x + 1 = x + 6   2. 3x − 4 = 2x + 3   3. 5x + 2 = 2x + 11   4. x + 7 = x + 2 📩 Drop your answers in the comments!

**In this lesson, you’ll learn how to solve simple algebraic equations.**   That means finding the value of the variable (like `x` or `y`) that makes the equation true. --- ### 🔹 **What is an Equation?** An **equation** is like a balance. It has **two sides** and an **equal sign (=)** between them. > **Example:**   > `x + 3 = 7` This means:   "What number added to 3 gives 7?" --- ### 🔸 **Step-by-Step Method** Let’s solve this: **`x + 3 = 7`** ➡️ **Step 1:** Subtract 3 from both sides: x + 3 − 3 = 7 − 3   x = 4 ✅ So the answer is: **x = 4** --- ### 🔸 **Example 2:** **`y − 2 = 5`** Add 2 to both sides: y − 2 + 2 = 5 + 2   y = 7 ✅ So the answer is: **y = 7** --- ### 🔸 **Example 3:** **`a ÷ 2 = 6`** Multiply both sides by 2: a ÷ 2 × 2 = 6 × 2   a = 12 ✅ So the answer is: **a = 12** --- ### ✨ **Important Rule to Remember:** > **Whatever you do to one side of the equation,**   > do the **same to the other si...

 In mathematics, a **variable** is a letter (like x or y) that represents a number. The number is not always known — it can change — that's why we call it a “variable.” ### 💡 Example 1: If `x = 3`, then: x + 2 = 3 + 2 = 5 ### 💡 Example 2: If `y = 7`, then: y - 4 = 7 - 4 = 3 ### 🔍 Why Do We Use Variables? We use variables to: - Represent unknown values - Write equations - Solve math problems more easily ### 🧠 Remember: A variable is just a **placeholder** for a number. ### ✅ Practice: Try solving these: 1. If `x = 5`, what is `x + 3`? 2. If `y = 10`, what is `y - 6`? 3. If `a = 4`, what is `a × 2`? Post your answers in the comments! 👇

 Algebra is a part of math where we use letters like x and y to represent numbers. For example: If x = 2, then x + 3 = 5 In this blog, I’ll teach you algebra step-by-step, using simple examples to help you understand. Stay with me, and math will become easier than ever!