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How to Solve Compound Inequalities

 Solving Compound Inequalities Compound inequalities are two inequalities joined by "and" or "or". They describe a range of values that satisfy both or either condition. --- 🔸 Types of Compound Inequalities 1. “And” Compound Inequality – Both conditions must be true – The solution is where the two inequalities overlap  Example: 1 < x ≤ 5  Means x is greater than 1 and less than or equal to 5 2. “Or” Compound Inequality – Either condition can be true – The solution includes both sides Example: x < –3 or x > 2 --- ✅ Example 1: Solve 1 < x + 2 ≤ 5 Step 1: Split into two parts: – 1 < x + 2 – x + 2 ≤ 5 Step 2: Solve each: – 1 < x + 2 → Subtract 2 → –1 < x – x + 2 ≤ 5 → Subtract 2 → x ≤ 3 ✅ Final Answer: –1 < x ≤ 3 --- ✅ Example 2: Solve x – 4 < –1 or x + 2 > 7 Step 1: Solve both parts: – x – 4 < –1 → Add 4 → x < 3 – x + 2 > 7 → Subtract 2 → x > 5 ✅ Final Answer: x < 3 or x > 5 Summary of Compound Inequalities  Type: "...

Graphing Inequalities on a Number Line

 Graphing Inequalities on a Number Line Visualizing inequalities on a number line helps us understand which values satisfy an inequality. This lesson shows you how to graph them step by step. --- 🔸 How to Graph an Inequality Steps to follow: 1. Draw a number line 2. Mark the value in the inequality 3. Use: Open circle (○) for or — value not included Closed circle (●) for or — value included 4. Shade the direction: Left for less than Right for greater than --- ✅ Example 1: Graph  Open circle at 4 Shade to the left <=========○---------  4 ✅ Final Answer: x < 4 --- ✅ Example 2: Graph  Closed circle at –2 Shade to the right --------●=========> -2 ✅ Final Answer: x ≥ –2 --- 🔸 Quick Summary: Symbols and Circles Symbol Type of Dot Includes the Number?  or Open circle (○) ❌ No  or Closed circle (●) ✅ Yes 📝 Practice Questions: Practice: Graph the following inequalities on a number line. 1. x > 2 2. x ≤ 0 3. x ≥ –5 4. x < –1 5. x ≥ 7 📘 Keep l...

Introduction to Inequalities

 What are Inequalities? In algebra, not all expressions are equal — some are greater or less than others. Inequalities help us compare values that are not exactly equal. --- 🔸 What is an Inequality? An inequality is a mathematical sentence that shows the relationship between two expressions using comparison symbols. --- 🔸 Common Inequality Symbols Symbol Meaning Example > Greater than x > 4 < Less than x < 7 ≥ Greater than or equal to x ≥ 2 ≤ Less than or equal to x ≤ 5 --- 🔸 Difference Between Equations and Inequalities An equation gives one exact answer:   ✅ x = 3 An inequality gives many possible answers:   ✅ x > 3 (x could be 4, 5, 100…) --- 🔸 Solving Inequalities Solving inequalities is almost the same as solving equations: You can add, subtract, multiply, or divide both sides. BUT, if you multiply or divide by a negative number, flip the sign. --- ✅ Examples Example 1: Solve x + 4 < 9 Step: Subtract 4 from both sides Answer: x < 5 Example 2: Solve –2x...

Like and Unlike Terms

Like and Unlike Terms In algebra, knowing which terms you can combine is important. That’s where the concept of like terms and unlike terms comes in. --- ✅ What Are Like Terms? Like terms are terms that: Have the same variable, and Have the same exponent (power) Only the coefficients (numbers in front) can be different. Examples of Like Terms: 2x and 5x 3a² and -7a² x and -x --- ❌ What Are Unlike Terms? Unlike terms have: Different variables, or The same variables but different powers Examples of Unlike Terms: 3x and 4y 2a and 2a² x and x² --- ✍️ Examples Example 1: Which of the following are like terms? 5y, -2y, 3x, 7y ✅ Like terms: 5y, -2y, 7y ❌ Unlike term: 3x Example 2: Group the like terms: 2m, 3n, -4m, 5n, 6 Like terms: 2m, -4m and 3n, 5n Constant: 6 (unlike any other) --- 📝 Practice Questions 1. Identify the like and unlike terms in this set: 6x, -3x, 4y, x² 2. Group the like terms in: 2a, 3b, 5a, -2b, 7 --- ✅ Keep learning! Stay tuned for the next topic! 📖 Visit our blog: eas...

Parts of an Expression

An algebraic expression is a combination of numbers, letters (variables), and mathematical operations such as addition, subtraction, multiplication, or division. ✅ Key Parts of an Expression 1. Term A term is any part of the expression that is separated by a plus (+) or minus (−) sign. Example: In the expression 3x + 4, there are two terms: 3x and 4. 2. Coefficient A coefficient is the numerical part of a term with a variable. Example: In 3x, the coefficient is 3. 3. Variable A variable is a symbol (often a letter like x or y) that represents an unknown value. Example: In 3x + 4, the variable is x. 4. Constant A constant is a fixed value with no variable attached. Example: In 3x + 4, the constant is 4. --- ✍️ Examples Example 1: Expression: 7y − 2 Terms: 7y, −2 Coefficient: 7 Variable: y Constant: −2 Example 2: Expression: 5a + 3b − 7 Terms: 5a, 3b, −7 Coefficients: 5, 3 Variables: a, b Constant: −7 --- 📝 Practice Questions 1. Identify the terms, coefficients, and constants in the exp...

Real-Life Word Problems Involving Fractions

Welcome back to EasyMathsGuid! In this lesson, we’re solving real-life word problems using fractions. These help you apply math to everyday situations. --- 🔶 Word Problem 1 A school bought 7 1/2 kilograms of rice for a math club event. They used 2 2/3 kilograms for lunch and 1 3/4 kilograms for dinner. Question: How much rice is left? --- 🧮 Solution: Step 1: Convert mixed numbers: 7 1/2 = 15/2 2 2/3 = 8/3 1 3/4 = 7/4 Step 2: Add lunch and dinner used: 8/3 = 32/12 7/4 = 21/12 Total used = 32/12 + 21/12 = 53/12 Step 3: Total rice = 15/2 = 90/12 Step 4: Leftover = 90/12 - 53/12 = 37/12 = 3 1/12 ✅ Final Answer: 3 1/12 kg of rice is left --- 🔷 Word Problem 2 Mary read 3/4 of a book in the morning and 2/5 in the evening. How much of the book did she read in total? --- 🧮 Solution: LCM of 4 and 5 = 20 3/4 = 15/20 2/5 = 8/20 Total = 15/20 + 8/20 = 23/20 = 1 3/20 ✅ Answer: Mary read 1 3/20 of the book --- 🔷 Word Problem 3 A water tank contains 5 1/2 liters of water. If 3 3/4 liters are used...

Solving Word Problems Involving Fractions in Equations

This lesson shows how to solve real-world problems where fractions are involved in the equation. It builds directly from Lesson 12 on dividing fractions. --- 🔍 Steps to Solve: 1. Read the word problem carefully. 2. Let the unknown number be x. 3. Translate the words into a fraction-based equation. 4. Solve by multiplying by the reciprocal or using the LCM method. 5. State your final answer clearly. --- 📘 Example 1: Problem: One-third of a number is 9. What is the number? Solution: Let the number be x. (1/3) × x = 9 Multiply both sides by 3: x = 9 × 3 = 27 ✅ Final Answer: 27 --- 📘 Example 2: Problem: Half a number minus 2 equals 3. Find the number. Solution: (1/2) × x - 2 = 3 Add 2 to both sides: (1/2) × x = 5 Multiply both sides by 2: x = 10 ✅ Final Answer: 10 --- 📘 Example 3: Problem: Two-thirds of a number equals 16. What is the number? Solution: (2/3) × x = 16 Multiply both sides by 3/2: x = 16 × (3/2) = 48/2 = 24 ✅ Final Answer: 24 --- 📝 Practice Questions: 1. One-fourth of a ...